(8x^2-40x+48)/(12-8x^2-20x)

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Solution for (8x^2-40x+48)/(12-8x^2-20x) equation:


D( x )

12-(8*x^2)-(20*x) = 0

12-(8*x^2)-(20*x) = 0

12-(8*x^2)-(20*x) = 0

12-8*x^2-20*x = 0

12-8*x^2-20*x = 0

DELTA = (-20)^2-(-8*4*12)

DELTA = 784

DELTA > 0

x = (784^(1/2)+20)/(-8*2) or x = (20-784^(1/2))/(-8*2)

x = -3 or x = 1/2

x in (-oo:-3) U (-3:1/2) U (1/2:+oo)

(8*x^2-(40*x)+48)/(12-(8*x^2)-(20*x)) = 0

(8*x^2-40*x+48)/(12-8*x^2-20*x) = 0

8*x^2-40*x+48 = 0

8*(x^2-5*x+6) = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

8*(x-2)*(x-3) = 0

12-8*x^2-20*x = 0

4*(3-2*x^2-5*x) = 0

3-2*x^2-5*x = 0

DELTA = (-5)^2-(-2*3*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+5)/(-2*2) or x = (5-49^(1/2))/(-2*2)

x = -3 or x = 1/2

4*(x+3)*(x-1/2) = 0

(8*(x-2)*(x-3))/(4*(x+3)*(x-1/2)) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 2, 3 }

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